CBSE NET Selection Procedure 2017:Central Board of Selection Procedure has announced the details of the selection procedure to be adopted for CBSE UGC NET. The National Eligibility Test (NET) conducted by Central Board of Secondary Education is was held on January 22 and the result has been declared on May 29, 2017. All the candidates who qualified the exam with exemplary performance and scores will be awarded Junior Research Fellowship and Eligibility for Assistant Professor or both. The candidates qualifying exclusively for Assistant Professor will not be considered for award of JRF. The candidates had to obtain minimum qualifying marks separately in Paper-I, Paper-II and Paper-III. As per the CBSE NET Selection Procedure 2017, the minimum qualifying marks for General Category candidates in Paper-I and II is 40 and Paper-III is 75. However, for OBC/PWD/SC/ST category candidates, the minimum qualifying marks for Paper-I and II is 35 and Paper-III is 60. It is mandatory for the candidates to secure the minimum qualifying marks to qualify in CBSE NET Exam. The detailed CBSE NET Selection Procedure 2017 has been explained below.
CBSE NET 2017 Minimum Qualifying Marks for Selection
The candidates appearing for CBSE NET 2017 exam need to qualify the exam by obtaining the following marks fixed by the Board. See below.
|OBC (Non-creamy layer) PWD/SC/ST
Procedure & Criteria for Selection in CBSE NET 2017
The procedure & criteria of selection in CBSE NET 2017 is explained in the following steps.
- Step I: The candidates need to obtain minimum marks to be obtained in NET for considering a candidate for the award of JRF and eligibility for Assistant Professor. They are required to obtain minimum marks separately in Paper-I, Paper-II, and Paper –III.
- Step II: Amongst those candidates who have cleared the step I, a merit list will be prepared subject-wise and category-wise using the aggregate marks of all the three papers secured by such candidates.
- Step III: Top 15% candidates (for each subject and category), from the merit list, mentioned under step II, will be declared NET qualified for eligibility for Assistant Professor only. By this method, if the number obtained is less than one, it is taken as at least one, i.e., a minimum of one candidate is qualified wherever a fraction less than one is obtained as per this methodology. However, for fractions greater than one, the figure is rounded off to the nearest whole number.
- Step IV: A separate merit list for the award of JRF will be prepared from amongst the NET qualified candidates figuring in the merit list prepared under step III.
Criteria for Awarding Junior Research Fellowships of CBSE NET 2017
- Out of the candidates who have qualified for Assistant Professor, those candidates who have applied for JRF will be considered for the award of JRF according to the slots available for JRF.
- The methodology for allocation of JRF slots among different subjects is done category-wise.
- The Commission provides a minimum of 3200 fellowships in each UGC-NET.
- As per Government of India reservation policy, a minimum of 27%, 15%, 7.5% and 3% of Fellowships are reserved for the OBC (Non-creamy layer), SC, ST and Persons with disabilities (PWD) respectively.
- The calculation is based on the ratio of the number of candidates who had opted for JRF and were qualified for lectureship eligibility in each subject category-wise to the total number of candidates qualified for lectureship who had opted for JRF in that category overall subjects multiplied by the total number of fellowships to be awarded to that category. The nearest whole number obtained as per this formula provides the number of slots available in any particular subject category-wise.
- If the number of JRF slots obtained for any subject in a particular category is less than one, it is taken as one, i.e., a minimum of one JRF is awarded wherever a fraction less than one is obtained as per this methodology. However, for fractions greater than one, the figure is rounded off to the nearest whole number.